# Am I doing this Right

1. Sep 9, 2004

### Tom McCurdy

I am very tired and am not sure if i am doing this right

$$convert into P=Poe^(^k^t^)$$

I came up with
$$P=15e^(^l^n^(^1^.^5^)^t^)$$
from
$$P=15(1.5)^t$$

haha
nvm i think i got it while I was trying to figure out latex
wow--- the answer was so easy it seemed wrong

2. Sep 10, 2004

### modmans2ndcoming

ti is always the easy ones that are difficult. I always hate when my Profs gear us up for the super involved stuff an then throw us some softballs... I end up messing them up because I make the problem harder than it really is.