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By the way, if it seems familiar it is on this thread, he must have had same textbook, https://www.physicsforums.com/archive/index.php/t-91330.html roffle

so d(klingon)= vt + 100

d(enterprise)= .5(vf - vi)t + vi(t) (I got from area under graph)

they are equal I thought when they stopped so I combined them:

vk(t) + 100 = .5(vf-vi)t + vi(t)

vk(t) + 100 = .5vi(t)

20t + 100 = 25t

t = 20 s

since I hope I have proven my attempt I ended up getting an accerlation of -2500 m/s^2

I am sort of confident I didn't make a mathematical error since I checked it a lot, so I assume I made a conceptual error. Answer in back is -4500 m/s^2. I must have underestimated the question?

Thanks for any help you might have to direct me and I am sorry I do not know how to make the equations fancy.