# Am I missing something?

x= (-b± $\sqrt{b^2-4ac}$)/2a

Am I missing something? I mean the value underneath the square root turns out to be a negative number, so technically this equation would not have worked right? It's from a textbook by the way. This is actually an analytical chemistry application question.

x= -6.8*10-4 ± [(6.8*10-4)2 - (4)(6.8*10-4)]0.5/(2)(1)

lurflurf
Homework Helper
The equation works fine with negative numbers. Sometimes this happens when the roots should be real, either a mistake was made or the situation modeled is impossible or there was rounding and the roots returned are barely complex and should be rounded back to real.

is b = c ?
or did you write the wrong value?

In any case, negative ARE possible and you go into complex number territory

phinds