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Homework Help: AMA and IMA with Leves

  1. Dec 10, 2009 #1
    1. The problem statement, all variables and given/known data
    ......Fulcrum-->...............4..............5................6..............7
    Effort Force (EF)
    (Measured EF+EA)--.... 12.1 N....... 12.8 N....... 14.3 N....... 17.6 N

    Resistance Force (RF)
    (RA+weight load(9.8))-. 25.0 N....... 26.0 N....... 27.0 N....... 28.1 N

    Effort Distance (Ed)..... 1.15 m...... 1.05 m...../ .950 m...../ .850 m

    Resistance Distance (Rd)...../ 0.54 m...../ .64 m .740 m...../ .840 m

    Effort Arm Weight (EA)
    (Ed/Td = x/Tw)- ........ 11.6 N....... 10.6 N....... 9.56 N....... 8.55 N

    Resistance Arm Weight (RA)
    (Rd/Td = x/Tw)--........ 15.2 N....... 16.2 N....... 17.2 N....... 18.3 N

    Mechanical Advantage.. 4....../5...../6...../7
    Ideal (Ed/Rd)--............2.13/ 1.64/ 1.28/ 1.01
    Actual (RF/EF)--......... 2.07/ 2.03/ 1.89/ 1.60



    2. Relevant equations
    My teacher has me solving AMA (RF/EF)with RF=weight of RA +weight of load 9.8, and EF=weight of EA+EF measured with scale. (results on chart). Also he wants me to solve IMA using EA/RA, where EA = distance from effort force to fulcrum, and RA = distance from load to fulcrum. This is the same thing as dividing Ed by Rd from the chart, unless I'm mistaken. When I work this out, the IMA is lower than the AMA, and I don't believe thats right. I really need some help

    I'm really sorry if this is very messy
     
  2. jcsd
  3. Dec 10, 2009 #2
    I believe that either I misunderstood the equation or the paper is incorrect.
     
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