AMA and IMA with Leves

1. Dec 10, 2009

SHHSPhysics

1. The problem statement, all variables and given/known data
......Fulcrum-->...............4..............5................6..............7
Effort Force (EF)
(Measured EF+EA)--.... 12.1 N....... 12.8 N....... 14.3 N....... 17.6 N

Resistance Force (RF)
(RA+weight load(9.8))-. 25.0 N....... 26.0 N....... 27.0 N....... 28.1 N

Effort Distance (Ed)..... 1.15 m...... 1.05 m...../ .950 m...../ .850 m

Resistance Distance (Rd)...../ 0.54 m...../ .64 m .740 m...../ .840 m

Effort Arm Weight (EA)
(Ed/Td = x/Tw)- ........ 11.6 N....... 10.6 N....... 9.56 N....... 8.55 N

Resistance Arm Weight (RA)
(Rd/Td = x/Tw)--........ 15.2 N....... 16.2 N....... 17.2 N....... 18.3 N

Ideal (Ed/Rd)--............2.13/ 1.64/ 1.28/ 1.01
Actual (RF/EF)--......... 2.07/ 2.03/ 1.89/ 1.60

2. Relevant equations
My teacher has me solving AMA (RF/EF)with RF=weight of RA +weight of load 9.8, and EF=weight of EA+EF measured with scale. (results on chart). Also he wants me to solve IMA using EA/RA, where EA = distance from effort force to fulcrum, and RA = distance from load to fulcrum. This is the same thing as dividing Ed by Rd from the chart, unless I'm mistaken. When I work this out, the IMA is lower than the AMA, and I don't believe thats right. I really need some help

I'm really sorry if this is very messy

2. Dec 10, 2009

SHHSPhysics

I believe that either I misunderstood the equation or the paper is incorrect.