# Ambiguous problem definition

Add the same digit twice in the following equation so that it becomes true. There are two possible solutions for this problem. Which are they? 16 x 2 = 8
I don't get it...
What are you supposed to do?
Right answers apparently are 2 and 3.

HallsofIvy
Homework Helper
16 times 2 is, in fact, 32 which is 4 times 8 so one possible answer us 16 x 2=2 x 2 x 8 where I have "added" ("inserted" would have been a better word) the digit 2 twice.

Using "3" is a bit of a stretch. $16*32= 8^3$

The whole problem is a bit of a stretch on the boundaries on reason...
Eh well... thanks anyway.

This was from some half-assed IQ test I encountered btw.