- #1

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Let A, M, and C be digits with:

(100A+10M+C)(A+M+C) = 2005

A. 1 B. 2 C. 3 D. 4 E. 5

maybe some one can help me out on this, was one of the test questions i did not know how to do.

- Thread starter cdhotfire
- Start date

- #1

- 193

- 0

Let A, M, and C be digits with:

(100A+10M+C)(A+M+C) = 2005

A. 1 B. 2 C. 3 D. 4 E. 5

maybe some one can help me out on this, was one of the test questions i did not know how to do.

- #2

- 13,017

- 566

I don't see other solution than

[tex] A=4;M=0;C=1 [/tex]

Daniel.

[tex] A=4;M=0;C=1 [/tex]

Daniel.

- #3

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- #4

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wow, i didnt notice that, hmmm, thxs.

- #5

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- #6

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Three circles of radius [itex]s[/itex] are drawn in the first quadrant of the xy-plane. The first circle is tangent to both axes, the second is tangent to the first circle and the x-axis, and the third is tangent to the first circle and the y-axis. A circle of radius [itex] r > s [/itex] is tangent to both axes and to the second and third circles. What is [itex] r/s [/itex]?

A. 5 B. 6 C.8 D. 9 E. 10

- #7

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That is a better method.t!m said:

- #8

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I drew a line from the center of the large circle to the center of the top small circle (tangent to the first circle and the y-axis) and used that as the hypotenuse for a right triangle with sides (r-3s), (r-s), and (r+s). This makes more sense if you're looking at the diagram. In which case, (r-s)^2 + (r-3s)^2 = (r+s)^2. I just tried each answer, and found r=9, s=1 (r/s=9) to be the one which works. If you're confused, I'll see if I can work up a diagram.

- #9

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In the five-sided star shown, the letters A, B, C, D and E are replaced by the numbers 3, 5, 6, 7 and 9, although not necessarily in that order. The sums of the numbers at the ends of the line segments [itex]\lin{AB},\lin{BC},\lin{CD},\lin{DE}[/itex] and [itex]\lin{EA}[/itex] form an arithmetic sequence, although not necessarily in that order. What is the middle term of the arithmetic sequence?

http://img103.exs.cx/img103/6466/amc7lx.gif

A. 9 B. 10 C. 11 D. 12 E. 13

- #10

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- #11

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o i see, i didnt understand the question. , thxs though.

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