(adsbygoogle = window.adsbygoogle || []).push({}); AMU Too many variables......?

1. The problem statement, all variables and given/known data

the atomic mass of lithium6 is 6.0151 and the amu of lithium-7 is 7.0160. calculate the natural abuncance of hese two isotopes. use the value of 6.941 amu as the value fr the average atomic mass of lithium

2. Relevant equations

ave atomic weight = (% of isotope 1)(amu of isotope 1)+(% of isotope 2)*(amu of isotope 2)

3. The attempt at a solution

Okay.. So the equation I set up ends up being

6.941 amu =X(7.0160)+Y(6.0151)

I have 2 variables, so here I get stuck.... I have no idea how to solve when I have 2 variables.....

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# Homework Help: AMU Too many variables ?

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