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Amusement park

  • Thread starter ZzZerozZ
  • Start date
  • #1
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Homework Statement



In an amusement park ride called The Roundup, passengers stand inside a 17.0m -diameter rotating ring. After the ring has acquired sufficient speed, it tilts into a vertical plane.

Suppose the ring rotates once every 4.80s . If a rider's mass is 52.0kg , with how much force does the ring push on her at the top of the ride?

Homework Equations


1.v=2*pi*r/T
2.Fr=mg+n=Fnet=m*Ac=m*v^2/r

The Attempt at a Solution



What I do is T=4.80 m=52.0kg

v=formula#1=11.126m/s
Ac= formula#2=14.56m/s^2
Fr=m*Ac= 757,12N

The answer is wrong but I don't know why....
 

Answers and Replies

  • #2
rock.freak667
Homework Helper
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The centripetal force, you are finding, is the resultant force on the rider. At the top of the ride, what are the forces acting and their directions?
 
  • #3
9
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n and Fg pointing downwards?
 
  • #4
rock.freak667
Homework Helper
6,230
31
n and Fg pointing downwards?
Right, I think the question wants you to find n. Your second equation n+Fg=Fr, find n.
 
  • #5
9
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OO.. yea thx a lot :D
 

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