# Amusement park

ZzZerozZ

## Homework Statement

In an amusement park ride called The Roundup, passengers stand inside a 17.0m -diameter rotating ring. After the ring has acquired sufficient speed, it tilts into a vertical plane.

Suppose the ring rotates once every 4.80s . If a rider's mass is 52.0kg , with how much force does the ring push on her at the top of the ride?

## Homework Equations

1.v=2*pi*r/T
2.Fr=mg+n=Fnet=m*Ac=m*v^2/r

## The Attempt at a Solution

What I do is T=4.80 m=52.0kg

v=formula#1=11.126m/s
Ac= formula#2=14.56m/s^2
Fr=m*Ac= 757,12N

The answer is wrong but I don't know why....

## Answers and Replies

Homework Helper
The centripetal force, you are finding, is the resultant force on the rider. At the top of the ride, what are the forces acting and their directions?

ZzZerozZ
n and Fg pointing downwards?

Homework Helper
n and Fg pointing downwards?

Right, I think the question wants you to find n. Your second equation n+Fg=Fr, find n.

ZzZerozZ
OO.. yea thx a lot :D