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## Homework Statement

In an amusement park ride called The Roundup, passengers stand inside a 17.0m -diameter rotating ring. After the ring has acquired sufficient speed, it tilts into a vertical plane.

Suppose the ring rotates once every 4.80s . If a rider's mass is 52.0kg , with how much force does the ring push on her at the top of the ride?

## Homework Equations

1.v=2*pi*r/T

2.Fr=mg+n=Fnet=m*Ac=m*v^2/r

## The Attempt at a Solution

What I do is T=4.80 m=52.0kg

v=formula#1=11.126m/s

Ac= formula#2=14.56m/s^2

Fr=m*Ac= 757,12N

The answer is wrong but I don't know why....