1. The problem statement, all variables and given/known data On one of the shelves in your physics lab is displayed an antique telescope. A sign underneath the instrument says that the telescope has a magnification of 20 and consists of two converging lenses, the objective and the eyepiece, fixed at either end of a tube 60.0 cm long. Assuming that this telescope would allow an observer to view a lunar crater in focus with a completely relaxed eye, what is the focal length Fe of the eyepiece? 2. Relevant equations Length (L) = Fo+Fe Which Fo = Focal length of the objective lens Fe = Focal length of the eyepiece M = -Fo/Fe 3. The attempt at a solution L = Fo+Fe 60 = Fo+Fe Fe = 60-Fo M = -Fo/Fe 20 = -(60-Fe) / Fe Which Fe would be -3.16 But I got wrong.. Please help me.. thank you..