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An easy integration,thanks.

  1. May 1, 2010 #1
    If f(t)=integral of 1/(1+x^2) from t^2 to 0,then f'(t)=?

    thanks very much.
  2. jcsd
  3. May 1, 2010 #2


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    The integral looks odd since t^2 > 0 and you have 0 as the upper limit.. However as it stands, f'(t)=-2t/(1 + t^4)
  4. May 3, 2010 #3
    Use integration of inverse trig functions.
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