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An explannation of gravity

  1. Oct 31, 2005 #1
    We put ball A and ball B by distance R, every atom in ball A has some positive charges and some negative charges, same as atoms in ball B.

    Now suppose every positive charge in ball A attracts every negative charge and repells every positive charge in ball B, and verse visa.

    Now we have all the single force add up, we find it equals to f=gxm1xm2/rxr

    I once did some calculation, it sounds looked right, but now I forgot the details.

    So, I believe, gravity is the shadow of electrostatic force.

    An easier way to see this is to put two atoms apart and calculate the forces between all positive and negative charges.

    You may find I was right. If not, please let me know why, be appreciate.
     
  2. jcsd
  3. Oct 31, 2005 #2

    Doc Al

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    OK, but realize that the net charge on each ball is zero.
    That's exactly what happens.
    Nope. The electrostatic force is zero. On the other hand, the gravitational force, which is associated with mass not charge, is given by Newton's law of gravity.
     
  4. Oct 31, 2005 #3

    rbj

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    sounds looked like a crank turning to me.
     
  5. Oct 31, 2005 #4
    Why is an atom attracts another atom? They are both zero net charged.

    My point is even in every atom the net charge is zero, but the distance between positive charge and negative change between two atoms will smaller than same charges.

    The net force end up a mighty small percentage of the electrcostatic attration force. This is what we called gravity.
     
  6. Oct 31, 2005 #5

    HallsofIvy

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    And the point of everyone who has answered is that you are wrong. Very delicate have been done to determine precisely the force given by the difference in distances you are talking about- they do not give anything like the gravitational force. It is also well known that "neutron stars"- which have NO positive or negative charges at all- have strong gravitational fields.
     
  7. Oct 31, 2005 #6

    daniel_i_l

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    Do you mean that oppisite charges will be pulled together?
    That also wont cause an attraction, cause an equal amount of + and - charges will be pulled from each atom, so for example, a + charge in mass1 pulls a - charge from mass2 closer to it, but at the same time a + from mass2 is being pulled by a - in mass 1...
     
  8. Oct 31, 2005 #7

    ZapperZ

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    Where EXACTLY does another attom "attracts" another atom? In molecules? In solids? Have you studied what happens there? Have you heard of orbital HYBRIDIZATION? Have you looked at what KINDS of atoms that can form such a thing? Have you studied orbital bonding and why certain atoms can form such bonds while others can't?

    No?

    Well you SHOULD, at least BEFORE you put forward such outlandish speculation. You may also want to re-read the PF Guildlines on speculative posting before you proceed any further.

    Zz.
     
  9. Oct 31, 2005 #8

    russ_watters

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    Well.... because your idea is wrong. It isn't magnetism, it's gravity.
    Nope. Still wrong. An object that has all it's magnetic poles aligned in such a way as to not have a balanced (note: unbalanced doesn't mean it isn't still zero) charge is a magnet. Magnets don't behave anywhere near the way objects in gravity behave.
     
  10. Oct 31, 2005 #9
    Why is gravity has the same nature as electical force? Is any other force has the form of f=c m1m2/rr?
     
  11. Oct 31, 2005 #10

    ZapperZ

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    That isn't a good enough reason! There are MANY instances in physics where the mathematical forms are similar. Doesn't mean they are all the same phenomena sharing the same mechanism! If this is your only argument for your "theory", you have a lot of holes to plug.

    Furthermore, electric fields are not the result of ANY "shielding" of anything. Yet, this is how you are modelling your gravitational interaction. So in your model, gravity and electric field are of a DIFFERENT nature. So it is YOU who has to account for why they have the same dependence on distance!

    I'm guessing you realize why your argument on why neutral atoms "attract" one another is no longer valid.

    Zz.
     
  12. Oct 31, 2005 #11
    Let's see this way. Calculate the force between one atom in ball A and another in ball B.

    Suppose the sample atom has p3 and e1, e2, e3 chagres, it is nutraul. The distance between the center of the two atoms is r, it is much larger than the dr which is the radin of the atom, then we have F=fp3e1+fp3e2+fp3e3+fp3e1+fp3e2+fp3e3-fp3p3-fe1e1-fe1e2-fe1e3-fe2e1-fe2e2-fe2e3-fe3e1-fe3e2-fe3e3.

    It end up an attraction force, it increases with the mass (total charge) and decreases with distance square.
     
    Last edited: Oct 31, 2005
  13. Oct 31, 2005 #12

    ZapperZ

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