- #1

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Hello,

Solve inequality [tex]x^2+2ix+3<0[/tex] where [tex]i^2=-1[/tex]

Solve inequality [tex]x^2+2ix+3<0[/tex] where [tex]i^2=-1[/tex]

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- Thread starter Dacu
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- #1

- 8

- 2

Hello,

Solve inequality [tex]x^2+2ix+3<0[/tex] where [tex]i^2=-1[/tex]

Solve inequality [tex]x^2+2ix+3<0[/tex] where [tex]i^2=-1[/tex]

- #2

ShayanJ

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- #3

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- #4

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- #5

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OK... So what is the solution then?

- #6

HallsofIvy

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Yes, it is. Do you understand that the inequality you originally post makes no sense?

You say "any inequality can transformed into an equality". Of course, you can just replace "<" or ">" with "=" but that is not what I would call "transforming"?

- #7

mathman

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- #8

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Inequality solutions are given by formula:

[tex]x=i(-1\mp \sqrt{4-a})[/tex] where [tex]a\in \mathbb R ^-[/tex]

- #9

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OK... Is there any reason in particular that you created this thread?

- #10

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Reason:

Applications on "The fundamental theorem of algebra".

Applications on "The fundamental theorem of algebra".

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