An integral with a fraction in it-need help finding the antiderivative

An integral with a fraction in it--need help finding the antiderivative

Homework Statement

I have the integral $$\int(\frac{20}{1+x^2} - 2)dx$$ where x = ± 3. To solve, I need to find the antiderivative of $$\frac{20}{1+x^2} - 2$$

Now, the worksheet actually gives the answer to the problem: The antiderivative is 37.961 or 37.962. However, I'm having trouble actually reaching that answer on my own; I have trouble with the antiderivatives of fractions.

Homework Equations

Lessee... I know that the antiderivative of 1/x is ln x. When it gets any more complex than that I get confused.

The Attempt at a Solution

First, I took $$\int(\frac{20}{1+x^2} - 2)dx$$ and turned it into $$\int(20(1+x^2)^-^1 - 2)dx$$

Then, I tried to take the antiderivative. I thought it would be: $$20ln(1+x^2)-2x.$$

Then I plugged in the x values, 3 and -3. With positive 3 plugged in, it came out to 40.052, with a negative 3 it came out to 52.052. I don't even have to finish it off with the subtraction to know that my final answer isn't right and that I missed a step (or two) somewhere. Only question is: What step did I miss? I have a feeling I was supposed to do something with the 20... And I think that there might have been more to taking the antiderivative of (1+x^2)^-1 then just turning it into a natural logarithm. Would someone please help me figure out what I forgot?

Try a trig sub or look up derivatives of inverse trig functions.

Defennder
Homework Helper
If you're using a trigo substitution, you may want to use this:
$$tan^2\theta + 1 = sec^2\theta$$

Don't be a victim of universal logarithmic differentiation!

$$\int\frac{20}{1+x^2}dx$$ doesn't equal $$20*ln|1+x^2|+c$$

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If you haven't touched trig int before:

let x = tanu
dx = tanu.secu

substitute these values for x and dx

Oh hush! We all know it's 20arctanx - 2x! Cut the kid some slack!

The reason the natural logarithm didn't work was because you need the derivative of the denominator in the numerator. The derivative of 1+x^2 is 2x, and as you can see, it ain't there.

Oh hush! We all know it's 20arctanx - 2x! Cut the kid some slack!

The reason the natural logarithm didn't work was because you need the derivative of the denominator in the numerator. The derivative of 1+x^2 is 2x, and as you can see, it ain't there.

I didn't know it three-four years ago :shy:... 