# Homework Help: An object fired upward at a speed of 3.000 m/s

1. Oct 28, 2004

### SpeedeRi2

Diff. ways possible for velocity of an object to be changing when speed is not!

just a fun question? It would be nice if u could answer it! I also have questions with the problem below!

can you help me w/ the rest of this problem.

at t= 0.0000 s. It reaches its max. height at time t. What is its velocity at the max. height? Assuming that g=(-9.81 m/s/s), calculate the max. height reached in meters:

Any kind of help is appreciated!

Last edited: Oct 28, 2004
2. Oct 28, 2004

### stunner5000pt

You can do this using $$\Delta K + \Delta U = 0$$

or you can use the kinematic equations to solve this

for $$\Delta K + \Delta U = 0$$
$$\frac{1}{2} m v_{i} = mgh_{2}$$

for the kinematic equations use
$$d = v_{1} t + \frac{1}{2} a t^2$$

3. Oct 29, 2004

### TriumphDog1

the velocity at its maximum point would be 0 because it is about to start falling back down.
using the formula $$V_{f}^{2} = V_{i}^{2} + 2ad$$, you can get the distance it travels upwards.
$$V_{f} =$$0
$$V_{i} =$$3
a = -9.8
Solve for d.