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Homework Help: An object fired upward at a speed of 3.000 m/s

  1. Oct 28, 2004 #1
    Diff. ways possible for velocity of an object to be changing when speed is not!

    just a fun question? It would be nice if u could answer it! I also have questions with the problem below!



    can you help me w/ the rest of this problem.

    at t= 0.0000 s. It reaches its max. height at time t. What is its velocity at the max. height? Assuming that g=(-9.81 m/s/s), calculate the max. height reached in meters:

    Any kind of help is appreciated! :smile:
     
    Last edited: Oct 28, 2004
  2. jcsd
  3. Oct 28, 2004 #2
    You can do this using [tex] \Delta K + \Delta U = 0 [/tex]

    or you can use the kinematic equations to solve this

    for [tex] \Delta K + \Delta U = 0 [/tex]
    [tex] \frac{1}{2} m v_{i} = mgh_{2} [/tex]

    for the kinematic equations use
    [tex] d = v_{1} t + \frac{1}{2} a t^2 [/tex]
     
  4. Oct 29, 2004 #3
    the velocity at its maximum point would be 0 because it is about to start falling back down.
    using the formula [tex]V_{f}^{2} = V_{i}^{2} + 2ad[/tex], you can get the distance it travels upwards.
    [tex]V_{f} =[/tex]0
    [tex]V_{i} =[/tex]3
    a = -9.8
    Solve for d.
     
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