A 12kg toboggan is pulled along at a constant velocity on a horizontal surface by a horizontal force of 11N.(adsbygoogle = window.adsbygoogle || []).push({});

a) What is the force of gravity on the toboggan?

b) What is the coefficient of friction?

c) How much horizontal force is needed to pull the toboggan at a constant velocity if two 57kg girls are sitting in it?

m=12kg

F_{A}= 11N

a) F_{g}=F_{N}

mg=F_{N}

12(9.8)=F_{N}

118N=F_{N}=F_{g}

F_{g}=118N

b) F_{A}=F_{f}; constant vel.

F_{K}=F_{A}=11N

Fk=μ_{K}F_{N}

11N= μ_{K}(118N)

μ_{K}=11N/118N

μ_{K}=0.093

c)m= 12kg + 2(57kg)= 126kg

F_{g}=F_{N}

mg=F_{N}

126(9.8)=F_{N}

1234.8N=F_{N}

m=126kg

F_{N}=1234.8N

F_{K}=F_{A}=?

im stuck here..

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# Analyzing motion with friction

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