A 12kg toboggan is pulled along at a constant velocity on a horizontal surface by a horizontal force of 11N. a) What is the force of gravity on the toboggan? b) What is the coefficient of friction? c) How much horizontal force is needed to pull the toboggan at a constant velocity if two 57kg girls are sitting in it? m=12kg FA= 11N a) Fg=FN mg=FN 12(9.8)=FN 118N=FN=Fg Fg=118N b) FA=Ff; constant vel. FK=FA=11N Fk=μKFN 11N= μK(118N) μK=11N/118N μK=0.093 c)m= 12kg + 2(57kg)= 126kg Fg=FN mg=FN 126(9.8)=FN 1234.8N=FN m=126kg FN=1234.8N FK=FA=? im stuck here..