THis isn't exactly a question however, its a method my teacher talked to me about and I don't quite understand. This is a way of getting greater accuracy, and attaining the higher grades. The question states, tan(angle) = 3/4 So instead of using tan^-1 (3/4) to get the angle with many digits, round it off and losing accuracy, she said: Drawing the triangle out results in: Using pythag you can work out the other side. Now you have: sin(angle) = 3/5 cos(angle) = 4/5 I have worked out the statement: 2Tsin(angle) = 3mg However, how do I apply what was attained from the triangle to this question? Thanks.