# Angle at Maximum Height

1. Nov 24, 2013

### Objection

1. The problem statement, all variables and given/known data

the initial velocity of a projectile is 150 m\s .the angle between the velocity vector and the trajectory at the projectile's maximum height is
a) 90
b) 45
c) zero
d) 63.1
e) 36.9

2. Relevant equations

Vox= vx = Vocosθ
Vy = Vosinθ-gt
Range (R) = (vo)^2*sin(2θ)/g
Maximum Height (H) = (vo)^2*(sinθ)^2/2g

3. The attempt at a solution

http://im40.gulfup.com/43qMA.jpg [Broken]

in this image we can see that the angle at the maximum height is 0 but I want to get sure ?

Last edited by a moderator: May 6, 2017
2. Nov 24, 2013

Correct.