# Angle between 2 planes

## Homework Statement

I got everything in the answer, just that my answer was 2∫ d∅ was from [0 to ∏]. Same answer, but different approach.

## The Attempt at a Solution

How can the angle between 2 planes be greater than ∏? I took 2∫ d∅ from [0 to ∏] because I considered 2 cases, where y > 0, and y < 0...

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This boils down to the angle between their normal vectors. If one vector is fixed in the sense that it is always the reference in relation to which the angle is measured, then the angle with the other one is in $[0, 2\pi]$. If the reference is not fixed, then either vector may be used as one, and then you have ambiguity in the definition of the angle, it can always be taken to be less and greater than $\pi$.

LCKurtz
I think using the standard interpretation of the angle between two planes, that angle is never greater than $\pi/2$. You calculate it by calculating the angle between the two normals using$$\theta =\arccos\left(\frac{n_1\cdot n_2}{|n_1||n_2|}\right)$$and taking the supplementary angle if that comes out between $\pi/2$ and $\pi$.