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Final said:There is a ball of mass m. It is at height L (see the picture).
The kinetic energy is fixed (=E). What is the angle a, for which the ball catches up the maximum height after one bounce?
The bounce is elastic.
Thanks,
Final.
Final said:There is a ball of mass m. It is at height L (see the picture).
The kinetic energy is fixed (=E). What is the angle a, for which the ball catches up the maximum height after one bounce?
The bounce is elastic.
Thanks,
Final.
Final said:Yes, this is easy: the ball must bounce when it is at the vertex of the parabola... the condition is: [tex] 2gL + v^2\sin^2{\Theta} - v^2\sin{2\Theta}=0 [/tex] (How do you solve this?)
But if the energy is not enough to to catch up the vertex??
Thanks
Final
The angle for maximum height of a ball bounce is 45 degrees.
This is because at 45 degrees, the initial vertical velocity of the ball is equal to its horizontal velocity, resulting in the ball traveling the farthest distance before hitting the ground.
Yes, the type of surface can affect the angle for maximum height. For example, on a softer surface, the ball may not bounce as high and therefore a slightly higher angle may be needed to achieve maximum height.
Yes, the angle for maximum height can vary for different types of balls. Heavier balls may require a slightly higher angle to reach maximum height, while lighter balls may achieve maximum height at a slightly lower angle.
Yes, the mathematical formula is θ = tan-1(h/2d), where θ is the angle, h is the maximum height, and d is the horizontal distance traveled by the ball before hitting the ground.