(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

Force F= (-6.93 N) + (7.85 N) acts on a particle with position vector r = (4.66 m) + (1.36 m). What are (a) the magnitude of the torque on the particle about the origin and (b) the angle between the directions of and ?

2. Relevant equations

3. The attempt at a solution

So I find (a) to be 46.0058 N*m which is correct and for (b) I use t/f*r

So 46.0058/sqrt(6.93^2+7.85^2)*sqrt(4.66^2+1.36^2) = .9050610046

sin-1(of that) = 64.8315006 = angle. But this is incorrect?

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# Homework Help: Angle of a F*r calculation

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