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**1. The problem statement, all variables and given/known data**

A stone is thrown off a high cliff with speed 30m/s at an angle 0 degrees. At what angle is the stone's velocity 2 seconds after it's thrown. (measired with respect to the horizontal x direction(angle will be negative))

**2. Relevant equations**

angle = tan(Vy/Vx)

**3. The attempt at a solution**

V = velocity

Vx = stays constant = 30m/s

Vy = Vyo + ay*t = 30 m/s + 19.6 m/s = 49.6 m/s

angle = tan(49.6/30) which is wrong