Angle of incidence question

  • #1
b]1. A light beam coming from an underwater spotlight exits the water at an angle of 68° to the vertical. At what angle of incidence did it hit the air-water interface from below the surface?


2. snell's law n1sin[tex]\Theta[/tex]1=n2sin[tex]\Theta[/tex]2



3. sin[tex]\Theta[/tex]1=1.33(sin68)
After doing this I took the inverse sin of it and it comes up as error on my calculator. I know it should be an easy question but I dont know where I am messing up.
 

Answers and Replies

  • #2
jgens
Gold Member
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It looks like you've got the equation set up wrong. It should read:

[tex]n_1\sin{(\theta_1)} = n_2\sin{(\theta_2)}[/tex]

Where [itex]n_1 = 1.33[/itex], [itex]n_2 = 1[/itex], and [itex]\theta_2 = 68[/itex].
 
  • #3
I knew it would be something dumb, thanks for your help.
 

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