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Angle of inclination

  1. Feb 4, 2009 #1
    a car of mass 1000kg moves round a banked track at a constant speed of 108km/h. the reaction of the wheels is at right angles to the track, the horizontal radius is 100m. calculate the angle of inclination of the track.



    2. Relevant equations
    tan(theta)= V^2/rg



    3. The attempt at a solution
    108km/h = 30m/s
    (theta)= Tan^-1(900/(100 x g))

    im confused as to what g actually stands for
     
  2. jcsd
  3. Feb 4, 2009 #2

    Doc Al

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    Staff: Mentor

    g is the acceleration due to gravity; g ≈ 9.8 m/s².
     
  4. Feb 4, 2009 #3
    so the equation should read:
    theta= tan^-1(900/(100x9.8))
     
  5. Feb 4, 2009 #4

    Doc Al

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    Staff: Mentor

    Yes.
     
  6. Feb 4, 2009 #5
    Thankyou very much, im sure i will return
     
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