A golf ball is hit from the ground into a building window 50m high and 50m away from starting point. Find the initial angle.
The Attempt at a Solution
I will work backwards for this question. I assume that the final y velocity (Vy) is 0m/s.
the first equation I do is: Vy^2= Viy^2 + 2ay(y)
I solve this equation for Viy and I get 31.32m/s.
Next I use the equation: Vy = Viy + ayt
I solve this equation for time and I get 3.192s.
Next I use d = vt and in respects to x. I solve for v (being the initial x velocity). For this I get Vix to be 15.66m/s.
Now I have initial x and y velocity and use inverse tan to solve for angle. I get the initial angle to be: 63 degrees.
Are my numbers and method correct?