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Homework Help: Angle of Projectile

  1. Sep 23, 2013 #1
    1. The problem statement, all variables and given/known data
    A golf ball is hit from the ground into a building window 50m high and 50m away from starting point. Find the initial angle.


    3. The attempt at a solution
    I will work backwards for this question. I assume that the final y velocity (Vy) is 0m/s.

    the first equation I do is: Vy^2= Viy^2 + 2ay(y)
    I solve this equation for Viy and I get 31.32m/s.

    Next I use the equation: Vy = Viy + ayt
    I solve this equation for time and I get 3.192s.

    Next I use d = vt and in respects to x. I solve for v (being the initial x velocity). For this I get Vix to be 15.66m/s.

    Now I have initial x and y velocity and use inverse tan to solve for angle. I get the initial angle to be: 63 degrees.

    Are my numbers and method correct?
     
    Last edited: Sep 23, 2013
  2. jcsd
  3. Sep 23, 2013 #2
    I believe my steps are correct.
     
    Last edited: Sep 23, 2013
  4. Sep 23, 2013 #3
    Why do you assume that the final vertical velocity is zero?
     
  5. Sep 23, 2013 #4
    The final y velocity I assume to be zero. I forgot to add in a part where it said that it hit the window at its max height of motion.

    Given these circumstances I am correct, no?
     
  6. Sep 23, 2013 #5
    With the clarification, your solution is correct.
     
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