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Angle of Projectile

  • #1

Homework Statement


A golf ball is hit from the ground into a building window 50m high and 50m away from starting point. Find the initial angle.


The Attempt at a Solution


I will work backwards for this question. I assume that the final y velocity (Vy) is 0m/s.

the first equation I do is: Vy^2= Viy^2 + 2ay(y)
I solve this equation for Viy and I get 31.32m/s.

Next I use the equation: Vy = Viy + ayt
I solve this equation for time and I get 3.192s.

Next I use d = vt and in respects to x. I solve for v (being the initial x velocity). For this I get Vix to be 15.66m/s.

Now I have initial x and y velocity and use inverse tan to solve for angle. I get the initial angle to be: 63 degrees.

Are my numbers and method correct?
 
Last edited:

Answers and Replies

  • #2
I believe my steps are correct.
 
Last edited:
  • #3
6,054
390
Why do you assume that the final vertical velocity is zero?
 
  • #4
The final y velocity I assume to be zero. I forgot to add in a part where it said that it hit the window at its max height of motion.

Given these circumstances I am correct, no?
 
  • #5
6,054
390
With the clarification, your solution is correct.
 

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