Well, right now I'm working on one helluva a problem... Basically, a projectile is given a velocity of V sub "o" (Vo). The launch angle is gamma degrees above an surfaced which is inclined theta degrees above the horizontal. I'm tasked with finding its range along the inclined surface as well as finding the optimal angle gamma to maximize the range.(adsbygoogle = window.adsbygoogle || []).push({});

So far, what I've done is rotate the coordinate system suh that the x-axis is along the inclined surface with the origin of the (x,y)-axis being the intersection of this inclined surface, the ground, and the initial launch point.

This provides for the following components of "G" (which I'm taking to be -9.8m/s^2). Gx = -g*Sin Theta and Gy = -g*Cos Theta. This took a lil goemetry to obtain (had to draw a couple diagrams in order to work it all out).

Then I solved for t = (2Voy/g)Sec theta as well as Vox = VoxCos(gamma + theta). Of coarse, I now see an error, as that Vox would be for (x,y) with respect to the ground, not the incline surface... I'll post where my correction has lead to in a second...

**Physics Forums - The Fusion of Science and Community**

# Angle of projection above an incline?

Know someone interested in this topic? Share a link to this question via email,
Google+,
Twitter, or
Facebook

- Similar discussions for: Angle of projection above an incline?

Loading...

**Physics Forums - The Fusion of Science and Community**