(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

car travels 18.2km due north then 43.2km at 53 degrees west of north. Find magnitude of car's resultant displacement.

b.) calculate the direction of the car's resultant displacement, measured counter-clockwise from the northerly direction.

2. Relevant equations

3. The attempt at a solution

Ax = 18.2sin(90) =18.2 Ay = 18.2cos(90) = 0

Bx = 43.2sin(143) = 26 By = 43.2cos(143) = -34.501

Cx = 44.2 Cy = -34.501

44.2^2 + -34.501^2 = 3143.82, square root of that = 56.07

arctan(-34.504/44.2) = -37.98 degrees

so part b says counter-clockwise from north, so wouldn't it be from 90 degrees so should the angle be 127.98? I entered that as an asnwer and it's wrong so not sure what I did wrong.

**Physics Forums | Science Articles, Homework Help, Discussion**

Dismiss Notice

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Angle of Vector

**Physics Forums | Science Articles, Homework Help, Discussion**