1. The problem statement, all variables and given/known data car travels 18.2km due north then 43.2km at 53 degrees west of north. Find magnitude of car's resultant displacement. b.) calculate the direction of the car's resultant displacement, measured counter-clockwise from the northerly direction. 2. Relevant equations 3. The attempt at a solution Ax = 18.2sin(90) =18.2 Ay = 18.2cos(90) = 0 Bx = 43.2sin(143) = 26 By = 43.2cos(143) = -34.501 Cx = 44.2 Cy = -34.501 44.2^2 + -34.501^2 = 3143.82, square root of that = 56.07 arctan(-34.504/44.2) = -37.98 degrees so part b says counter-clockwise from north, so wouldn't it be from 90 degrees so should the angle be 127.98? I entered that as an asnwer and it's wrong so not sure what I did wrong.