1. The problem statement, all variables and given/known data V1 = -6i + 8j 2. Relevant equations arctan theta 3. The attempt at a solution arctan 8/(-6) = -53 deg To me this is a little confusing because its negative 53 degrees which is in the fourth quadrant but i reality its in the second quadrant. Do I always have to do an additional math plus graphical test to see where it is and the actual degree of vector 1? For example To see the degree of V1 i have to do 180 - 53 to get an angle of 127 degrees. But is there a way that I just plug it in and it gives me the correct degree in the right quadrant right away?