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Solve 2cosec2x = 3 for the range 0 <= x <= 360
cosec2x = 3/2
sin2x = 2/3
2x = 41.8...
this means 41.8.. / 2 AND (180 - 41.8...) / 2
now there is 2 other angle that make this true. How do I find them.
Thanks :)
cosec2x = 3/2
sin2x = 2/3
2x = 41.8...
this means 41.8.. / 2 AND (180 - 41.8...) / 2
now there is 2 other angle that make this true. How do I find them.
Thanks :)