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aliaze1
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Homework Statement
A 1.0-cm-thick layer of water stands on a horizontal slab of glass. A light ray in the air is incident on the water 60 degrees from the normal.
What is the ray's direction of travel in the glass?
Homework Equations
n΄sinθ΄ = n¹sinθ¹
or, if that is confusing,
n1sinθ1 = n2sinθ2
The Attempt at a Solution
The index of refraction for water is 1.33, and the index of refraction for air is 1
therefore i set up the problem as:
(1)sin(60) = (1.33)sinθ
θ should = about 40.628 degrees, but the computer says it is incorrect... where am I going wrong?
thanks
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