M, a solid cylinder (M=1.59 kg, R=0.127 m) pivots on a thin, fixed, frictionless bearing. A string wrapped around the cylinder pulls downward with a force F which equals the weight of a 0.750 kg mass, i.e., F = 7.357 N. Calculate the angular acceleration of the cylinder. I used, I*alpha= mgr (1/2)mr^2 *alpha= mgr (1/2)(1.59)(.127)^2 * alpha= (1.59)(9.8)(.127) Solving for alpha gave me 155.9 rad/s^2 which wasn't right. Can someone help? Thanks.