Angular Acceleration/ Find angle in period -- PLEASE help! I'm having trouble with part "B" please help. A.)A dentist's drill starts from rest. After 4.95 s of constant angular acceleration, it turns at a rate of 28600 rev/min. Find the drill's angular acceleration. An- swer in units of rad/s^2. B.)Find the angle through which the drill rotates during this period. Answer in units of rad. A.) [(28600*2pi)/60]/4.95 = 605.047 rad/s^2 B.) [(28600*2pi)/60] * 4.95 = 14825 rad. (but this is not the right answer?) Am I using the wrong formula? Any help appreciated.