# Angular acceleration of a fan

angular acceleration of a fan!!!!!!!!!!

## Homework Statement

An electric fan is turned off, and its angular velocity decreases uniformly from 500 rev/min to 200 rm rev/min in 4.00 s.
Find the angular acceleration in rev/s and the number of revolutions made by the motor in the 4.00 interval.

## The Attempt at a Solution

I got -1.25 for alpha in rev/sec^2, which is correct.

How come the number of revolutions isn't 5 revolutions?
(alpha) (time)=
(-1.25)(4 sec)=5 rev (-5) rev

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gneill
Mentor

Acceleration x time = velocity, not distance!

ohhhhhhhhhhh........ ok thanks. hmmm....... i'm not sure what formula i should use. i was going to try x=xo+vot+1/2at^2 but i can;t. ..................

gneill
Mentor

ohhhhhhhhhhh........ ok thanks. hmmm....... i'm not sure what formula i should use. i was going to try x=xo+vot+1/2at^2 but i can;t. ..................
Why not? (assuming of course that you'd use the angular form of the equation)

i dont have xo right?
we didn't cover this yet.......

gneill
Mentor

i dont have xo right?
we didn't cover this yet.......
Assume xo is zero. The count of revolutions (distance) begins, and the clock starts ticking, at the instant the fan is turned off.

okay so :

0+(-1.25 rev/s^2)(4 sec)+ 1/2(-1.25 rev/s^2)(4^2)
x=-5.00+ -12.50
x=-17.50

how do i make this angular?

gneill
Mentor

okay so :

0+(-1.25 rev/s^2)(4 sec)+ 1/2(-1.25 rev/s^2)(4^2)
x=-5.00+ -12.50
x=-17.50

how do i make this angular?
You're using angular values, so it's angular.

But you've got a problem. You're using an acceleration where the initial angular velocity is required.