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Angular acceleration of mass

  1. Mar 28, 2015 #1
    1. The problem statement, all variables and given/known data

    A uniform plate of mass m is suspended as shown.What will be the angular acceleration immediately after connection at B has been released?

    http://i.stack.imgur.com/1hMuk.png

    2. My attempt-

    I used torque=M.I*angular acceleration

    I chose the axis to be perpendicular to the plane at A where M.I=5mc^2/12 and at a distance of c/2 from line of action of mg by putting it in equation we get angular acc.=1.2g/c but the given ans. is 2.4g/c

    But when I solve choosing the axis as centre of mass -
    The tension/force by which string will pull= mg/2 and distance of line of action from axis =c/2 and M.I about c.m=5mc^2/48 and using torque =M.I*angular acceleration i get the right ans. I don't know what's the mistake in my 1st approach.
     
    Last edited: Mar 28, 2015
  2. jcsd
  3. Mar 28, 2015 #2
    Where is the diagram?
     
  4. Mar 28, 2015 #3
    Thanks for pointing. I corrected it.
     
  5. Mar 28, 2015 #4
    I think you calculated the lever arm incorrectly. If you choose point A, the lever arm that is perpendicular to the line of action is (c/2)/2 or c/4
     
    Last edited: Mar 28, 2015
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