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Introductory Physics Homework Help
Calculating Angular Acceleration for a Rotating Compact Disc
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[QUOTE="gcombina, post: 4603761, member: 495467"] Problem(physics class 201/Portland Community College) During the time a compact disc (CD) accelerates from rest to a constant rotational speed of 477 rev/min, it rotates through an angular displacement of 0.250 rev. What is the angular acceleration of the CD? (a) 358 rad/s2 (c) 901 rad/s2 (e) 794 rad/s2 (b) 126 rad/s2 (d) 866 rad/s2 This is my formula from my Kinetics formula in my book where ∂ = angular acceleration (1)Kinetics formula V^2 = V(initial)^2 + 2ax (2)so I converted to: ω^2 = ω(initial)^2 + 2∂θ (477 rev/mins)^2 = (0 rad/s)^2 + 2(∂)(0.250 rev) [(477 rev/mins)^2 - (0 rad/s)^2)]/ (2 (0.250 rev))= ∂ [(477 rev/mins)^2 - 0] / (.50 rev) = ∂ (477 rev/mins)^2 / .50 rev = ∂ (227529 rev^2/mins^2) / .50 rev = ∂ 455,058 rev/mins^2 = ∂ **** I can not get the answer! the Answer is "e" **** [/QUOTE]
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Calculating Angular Acceleration for a Rotating Compact Disc
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