1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Homework Help: Angular acceleration problem

  1. Nov 6, 2005 #1
    A rod of length 57.0 cm and mass 1.90 kg is suspended by two strings which are 41.0 cm long, one at each end of the rod. The string on side B is cut. Find the magnitude of the initial acceleration of end B.

    I tried using torque= I* alpha
    torque= L x f= (.57)(18.62)=10.6
    I got from Newton's 2nd law, (9.8)(1.90)
    so, 10.6 = I* alpha
    I= (1/12)(mL^2)= (1/12)(1.90 * (.57)^2= .051
    so, 10.6 = .051 alpha
    alpha = 207.8 rad/s^2
    alpha= a/L
    207.8 = a / .57
    a= 118.4 m/s ^2

    This isn't right... can someone please help me?
  2. jcsd
  3. Nov 6, 2005 #2


    User Avatar
    Homework Helper

    First, the place that it is rotating around is at one end of the rod.
    How far from this is the rod's center-of-mass?

    Newton's 2nd law is "Sum of Forces = ma"
    Maybe you mean Newton's 4th Law "Force by gravity = m g = m GM/r^2"
Share this great discussion with others via Reddit, Google+, Twitter, or Facebook