# Angular Acceleration/Velocity

1. Apr 28, 2013

### CollegeStudent

1. The problem statement, all variables and given/known data

A laboratory apparatus consists of a low friction, low mass turntable which carries a large, flat, round, solid disk. The disk is 10.0 inches or 25.4 cm in diameter and has a mass of 4.34 kg. The turntable base turns on a cylinder 1 7/8 inches (4.76 cm) in diameter. A string is wrapped around the base cylinder (hub) of the turntable. The string passes over pulley of negligible friction and mass to a hanging mass of 200 g. The hanging mass is released from rest and falls 80.0 cm in 7.05 s. (a) What is the acceleration of the falling mass assuming constant acceleration? (b) What is the angular acceleration of the turntable? Through how many radians does the turntable turn in the 7.05 seconds? How many revolutions is this? What is the angular velocity and the tangential velocity of an object attached to the edge of the large disk at the end of the 7.05 s?

2. Relevant equations

3. The attempt at a solution

Well I'll write down every variable I have

DISK:
Diameter = 25.4cm
Mass = 4.34 kg

CYLINDER:
Diameter = 4.76 cm

HANGING MASS:
200 kg
Velocity_i = 0
Δy = 80.0cm
Time = 7.05s

(a) What is the acceleration of the falling mass assuming constant acceleration?

So for this, knowing that acceleration is constant and this is a linear acceleration I can use

Δy = v_i * t + 1/2 * a * t²

we want a so

a = 2(Δy - (v_i * t)) / t²
0
a = 2Δy / t²
a = 2(.80m) / 7.05s² = .032m/s²

(b) What is the angular acceleration of the turntable? Through how many radians does the turntable turn in the 7.05 seconds? How many revolutions is this? What is the angular velocity and the tangential velocity of an object attached to the edge of the large disk at the end of the 7.05 s?

This is where I get stuck...I know that I can use

ω = ω_o + α * t
Δθ = ω_o * t + 1/2 * α * t²
ω² = ω_o ² + 2 * α * t²

I mean I can rearrange each one for α

α = (ω - ω_o) / t
α = 2(Δθ - (ω_o * t)) / t²
α = (ω² - ω_o²) / 2t²

But I don't know the final angular velocity, nor the Δθ because I don't know how many times it will spin.

Can anyone give me a hint here?

2. Apr 28, 2013

### Staff: Mentor

Your linear acceleration looks okay. Do you happen to know an expression that relates linear acceleration to angular acceleration? (hint: it involves the radius)

3. Apr 28, 2013

### CollegeStudent

I think I saw somewhere that Angular acceleration is = to linear acceleration / the radius? Is that correct?

4. Apr 28, 2013

### Staff: Mentor

Yes.

5. Apr 28, 2013

### CollegeStudent

Perfect....so then if

α = a/R
α = .032m/s² / R

But now.....it asks for the angular acceleration of the turntable.... is this the disk on TOP of the turntable...or the cylinder that the string is wrapped around and the turntable base turns on?

6. Apr 28, 2013

### Staff: Mentor

Yes

They are the same, as they are joined together and rotate together. But the string is tangential to only one of them...

7. Apr 28, 2013

### CollegeStudent

ahh okay so the cylinder is what I'll be using in this example...

so then

α = a / R
α = .032m/s² / .0476m = .672

so now

Through how many radians does the turntable turn in the 7.05 seconds

Wouldn't I just multiply that number by 2∏?

If that is true then this next part of:
How many revolutions is this?

seems redundant since it would be right back to .672

So I'm thinking my hunch is incorrect lol

8. Apr 28, 2013

### Staff: Mentor

No, acceleration is not a distance. How do you find distance given acceleration and time?

9. Apr 28, 2013

### CollegeStudent

Figures I would use the diameter rather than the radius -_- lol okay lets try that again

α = .032 m/s² / .0238m
α = 1.34

Δθ = ω_o * t + 1/2 * α * t²
Δθ = 1/2 * α * t²
Δθ = 1/2 * (1.34) * (7.05)²

How many revolutions is this?

NOW I would DIVIDE that number by 2∏ to get the revolutions correct?

so

33.3 / 2∏ = 5.30 revolutions

good so far?

10. Apr 28, 2013

### Staff: Mentor

The method's fine so far.

You might want to hang onto a few more decimal digits for intermediate results. Rounding errors are starting to creep into your significant digits. In general, when a problem has many steps where results build in previous results, you want to keep extra "guard digits" for the intermediate values. You still report individual results rounded to the required significant figures, but use the extra digits for following calculations.