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Angular acceleration with rpms

  1. Nov 2, 2004 #1
    Can someone walk me through this problem?

    A power drill reaches 13164 rpm in 1.01 seconds. What is the angular acceleration?

    The answer listed is 3.791 rad/s2, but I don't know how to get there.

    So far, I did (13164 rev x 2pi)/60 seconds to get 1378.5 rad/s (which is 'w', right)? but change in 'w' from 0-1378.5 / change in 't' from 0-1.01s isn't right.
    Please help.
  2. jcsd
  3. Nov 2, 2004 #2

    Doc Al

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    Staff: Mentor

    The listed answer makes no sense. Are you stating the problem completely?
  4. Nov 2, 2004 #3
    angular acceleration problem

    Thanks for responding. I found this problem on a site for practice problems (link listed below). I copied and pasted the question and answer directly from the page. I am confused.

  5. Nov 2, 2004 #4

    Doc Al

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    Staff: Mentor

    I went to that site and looked at 3 problems. Only one gave the correct answer; two, gave goofy answers, just like the problem you presented. Forget it. (You may wish to complain to the site owners.)
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