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aghakarim
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5. A roller 0.44 m diameter rolls down a slope starting from rest. It takes 12 seconds make 6 complete rotations along the sloping surface accelerating uniformly as it moves. Calculate the following:
(1). The angular velocity at the end.
(2). The linear velocity at the end.
(3). The angular acceleration.
(4). The linear acceleration.
(5). The distance travelled.
from the question its obvious each rotation takes two seconds
12/6=2
then i thought omega= (2*pi)/12 gives you rads per second
but i then got really confused as i actualy don't have the velocity in the question and i lost it all
is the angular velocity (number of revs*2*pu)/number of cycle?
any ideas? i am losttt!
(1). The angular velocity at the end.
(2). The linear velocity at the end.
(3). The angular acceleration.
(4). The linear acceleration.
(5). The distance travelled.
from the question its obvious each rotation takes two seconds
12/6=2
then i thought omega= (2*pi)/12 gives you rads per second
but i then got really confused as i actualy don't have the velocity in the question and i lost it all
is the angular velocity (number of revs*2*pu)/number of cycle?
any ideas? i am losttt!