A mass m is suspended vertically by a spring of force constant k. Derive the relation [itex]\omega \geq \sqrt{\frac{k}{m}}[/itex] where [itex]\omega[/itex] is the (angular) frequency of oscillation. The only way I know to do this is to solve the differential equation [itex]\ddot{y} + \frac{k}{m}y = 0[/itex] using [itex]y = A\cos(\omega t + \phi)[/itex] which gives [itex]\omega = \sqrt{\frac{k}{m}}[/itex]. Where does the [itex]\geq[/itex] sign come from?(adsbygoogle = window.adsbygoogle || []).push({});

Thanks.

James

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# Angular frequency of oscillation

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