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## Homework Statement

A 1.47kg particle moves in the xy plane with a velocity of

**v**= (4.59i - 3.28j)m/s. Determine the magnitude of the particle's angular momentum when its position vector is

**r**= (1.35i + 2.57j)m.

## Homework Equations

p = mv

L = r x p (the x is supposed to be a cross product and not a variable)

L = r x mv

## The Attempt at a Solution

First I scaled the velocity vector:

**v**= (4.59i - 3.28j)m/s by the mass, 1.47 kg, to get a new momentum vector (6.75i - 4.82j)kg*m/s.

Then I took the cross product of the

**r**vector with the new momentum vector:

(1.35i + 2.57j)m x (6.75i - 4.82j)kg*m/s (I let a=1.35, b=2.57, c=0, d=6.75, e=-4.82, and f=0, the got the k vector cross product by doing k=ae-bd)

The answer I got was -23.9 kg*m^2/s, which wasn't right.

What did I do wrong? Am I even anywhere near the correct solution/answer?

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