A 1.47kg particle moves in the xy plane with a velocity of v = (4.59i - 3.28j)m/s. Determine the magnitude of the particle's angular momentum when its position vector is r = (1.35i + 2.57j)m.
p = mv
L = r x p (the x is supposed to be a cross product and not a variable)
L = r x mv
The Attempt at a Solution
First I scaled the velocity vector: v = (4.59i - 3.28j)m/s by the mass, 1.47 kg, to get a new momentum vector (6.75i - 4.82j)kg*m/s.
Then I took the cross product of the r vector with the new momentum vector:
(1.35i + 2.57j)m x (6.75i - 4.82j)kg*m/s (I let a=1.35, b=2.57, c=0, d=6.75, e=-4.82, and f=0, the got the k vector cross product by doing k=ae-bd)
The answer I got was -23.9 kg*m^2/s, which wasn't right.
What did I do wrong? Am I even anywhere near the correct solution/answer?