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Angular momentum eigenstates and total mom. S?

  1. May 30, 2005 #1
    My problem is with finding total angular momentum S of a spin 2 particles. My quantum book doesn't do any examples with spin 2 particles do i just do
    J(J+1)|j,m> and just plug in j and that will be my value.
  2. jcsd
  3. May 31, 2005 #2
    Assuming zero orbital angular momentum, L = 0, then the eigenvalue of the total angular momentum squared is just S^2 = s(s+1)*(h-bar)^2, with s = 2.

    Generally, the treatment of the problem is the same as with spin-1/2 particles, so the orbital- and spin-components of angular momentum add together as usual in the case of non-zero orbital angular momentum, ie j goes between abs(l - s) and abs(l+s) in integer steps, then l(l+1)*(h-bar)^2 is the eigenvalue of L^2.

    Last edited: May 31, 2005
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