A particle has a mass of 2kg and moves in the xy plane with a constant speed of 3m/s along the direction of the vector r = i + j. What is the particle's angular momentum relative to the point (0,5) meters?
L = rmv
L = mvrsin(theta)
The Attempt at a Solution
I am studying for my exam and i am a little confused about this problem.
I know the answer is 21 kgm2/s
and the work to get that answer is (2kg)(3m/s)(5m)sin(45) = 21
So i get where the mass (2kg) and the velocity (3m/s) go in the equation but i dont get why the 5m is in there and how would i know to use the angle 45 degrees?
Thanks for any help on clarifying this up for me :)