1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Angular Momentum of a clock

  1. Nov 9, 2007 #1
    [SOLVED] Angular Momentum

    1. The problem statement, all variables and given/known data

    Find the magnitude of the angular momentum of the second hand on a clock about an axis through the center of the clock face. The clock hand has a length of 15.0cm and a mass of 6.00g. Take the second hand to be a slender rod rotating with constant angular velocity about one end.


    3. The attempt at a solution

    Clock hand: 15.0 cm --> .15m
    Mass: 6.00 g --> .006kg

    L=I(omega)

    To get omega:
    The second hand does one revolution in 60seconds.

    so 1/60 = .01667 rev/s --> .10472 rad/s

    To get I:

    I = 1/3 ML^2

    I = (.006)(.15)^2 = .000135

    Now that we got I and omega,

    L = (.000135)(.10472)
    L = .0000141372

    I would have thought that this procedure would have been right, but I got it incorrect.

    Final Answer: L= _________ kg m^2/s

    Please and thank you. :smile:
     
  2. jcsd
  3. Nov 9, 2007 #2

    Doc Al

    User Avatar

    Staff: Mentor

    You forgot to multiply by 1/3.
     
  4. Nov 9, 2007 #3
    you have good eye. Thank you for your help. :)
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?



Similar Discussions: Angular Momentum of a clock
  1. Angular momentume (Replies: 7)

  2. Angular momentum (Replies: 1)

Loading...