[SOLVED] Angular Momentum 1. The problem statement, all variables and given/known data Find the magnitude of the angular momentum of the second hand on a clock about an axis through the center of the clock face. The clock hand has a length of 15.0cm and a mass of 6.00g. Take the second hand to be a slender rod rotating with constant angular velocity about one end. 3. The attempt at a solution Clock hand: 15.0 cm --> .15m Mass: 6.00 g --> .006kg L=I(omega) To get omega: The second hand does one revolution in 60seconds. so 1/60 = .01667 rev/s --> .10472 rad/s To get I: I = 1/3 ML^2 I = (.006)(.15)^2 = .000135 Now that we got I and omega, L = (.000135)(.10472) L = .0000141372 I would have thought that this procedure would have been right, but I got it incorrect. Final Answer: L= _________ kg m^2/s Please and thank you.