Angular momentum of a particle problem

In summary, angular momentum is a measure of rotational motion and is defined as the product of moment of inertia and angular velocity. It is related to linear momentum through the equation L = r x p, and is conserved in closed systems unless acted upon by external torque. The formula for calculating angular momentum is L = I x ω or in some cases, L = mvr. The factors that affect angular momentum include mass, linear velocity, distance from the axis of rotation, and external torques.
  • #1
yuki_meiseki
2
0

Homework Statement


Two identical particles have equal but opposite momenta, p and -p, but they are not traveling along the same line show that the total angular momentum of this system does not depend on the choice of origin.


Homework Equations


L=r x p
Sum of torque = dL/dt


The Attempt at a Solution


Do not understand the problem at all.
 
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  • #2
Total angular momentum is r1xp+r2x(-p). If you change the origin, r1 changes to r1+d and r2 changes to r2+d. Conclusion?
 
  • #3


I can help clarify the problem for you. Angular momentum is a property of a particle that describes its rotational motion. It is defined as the cross product of the position vector (r) and the linear momentum (p) of the particle. In this problem, we have two identical particles with opposite momenta, but they are not traveling along the same line. This means that they are moving in different directions.

The total angular momentum of a system is the sum of the individual angular momenta of all the particles in the system. In this case, since the two particles have equal but opposite momenta, their individual angular momenta will cancel out, resulting in a total angular momentum of zero. This is because the cross product of a vector with its negative counterpart will always result in a vector with a magnitude of zero.

Now, the problem states that the total angular momentum of this system does not depend on the choice of origin. This means that the location from which we measure the position vector (r) does not affect the total angular momentum of the system. This can be proven mathematically by taking the derivative of the total angular momentum with respect to time (dL/dt) and showing that it is equal to zero, indicating that the total angular momentum is constant regardless of the choice of origin.

In conclusion, the total angular momentum of a system of two particles with equal but opposite momenta will always be zero, and it is independent of the choice of origin. This is because the particles' individual angular momenta cancel out, resulting in a net angular momentum of zero, and the choice of origin does not affect this cancellation.
 

1. What is angular momentum?

Angular momentum is a measure of the rotational motion of a particle or system of particles. It is defined as the product of the particle's moment of inertia and its angular velocity.

2. How is angular momentum related to linear momentum?

Angular momentum and linear momentum are related through the equation L = r x p, where L is angular momentum, r is the position vector, and p is the linear momentum. This means that any change in linear momentum will result in a corresponding change in angular momentum.

3. What is the conservation of angular momentum?

The conservation of angular momentum states that the total angular momentum of a closed system remains constant, unless acted upon by an external torque. This means that if there are no external torques acting on a system, the total angular momentum of the system will remain constant.

4. How do you calculate angular momentum?

The formula for calculating angular momentum is L = I x ω, where L is angular momentum, I is the moment of inertia, and ω is the angular velocity. In some cases, the formula may be simplified to L = mvr, where m is the mass, v is the linear velocity, and r is the distance from the axis of rotation.

5. What factors affect the angular momentum of a particle?

The angular momentum of a particle is affected by its mass, linear velocity, and distance from the axis of rotation. Additionally, any external torques acting on the particle will also affect its angular momentum. In a closed system, the angular momentum will remain constant, but if external torques are present, the angular momentum may change.

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