Angular Momentum of a system of particles

[dumdum000333]

Homework Statement

Two particles move in opposite directions along a straight line. Prticle 1 of mass m1 = 26kg at x1 = 23 m moves with a speed v1 = 43 m/s(to the right), while the particle 2 of mass m2 = 63 kg at x2= -22 m moves with a speed of -37 m/s(to the left).
Given: Counter clockwise is the positive angular diretion.

what is the total angular momentum of the system about the z-axis relative to point A along y-axis if A is at (0,-17m)?

Homework Equations

Lsystem=L1+L2
L=rXp
p=mv

The Attempt at a Solution

the angular momentum about A for particle 1 would be 17X(26)(43) which would be clockwise making a negative L so L1=-19006kgm^2/s
for particle2 it would be 17X(63)(37) counter clockwise spin about A so L2= 39627
L1+L2= 20621, but this does not seem to be correct

 

[dumdum000333]

the 2 particles are located on the x-axis if that helps at all

 

[Moetasim]

.

Your approach is correct, but there is a mistake in your calculations. The angular momentum for particle 1 should be -19006 kgm^2/s, as it is moving in the clockwise direction. However, for particle 2, the angular momentum should be -39627 kgm^2/s, as it is also moving in the clockwise direction. Therefore, the total angular momentum of the system about the z-axis relative to point A would be -58633 kgm^2/s.