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Angular Momentum of Earth

  1. Nov 17, 2013 #1
    1. The problem statement, all variables and given/known data
    Determine the angular momentum of the Earth about its rotation axis (assume the Earth is a uniform sphere).


    2. Relevant equations
    L = Iω
    I = (2/5)Mr^2
    ω = 2[itex]\pi[/itex]/T


    3. The attempt at a solution
    I = (2/5)(6.0 X 10^24 kg)(6.4 X 10^6m)^2
    ω = 1.992 X 10^-7 rad/sec

    L = (2/5)(6.0 X 10^24 kg)(6.4 X 10^6m)^2 * (1.992 X 10^-7 rad/sec)
    What I get from this is 1.958 X 10^31 and the answer is supposed to be 7.1 X 10^33. where did I go wrong? Thank you
     
  2. jcsd
  3. Nov 17, 2013 #2

    TSny

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    How long does it take the earth to rotate one revolution on its axis?
     
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