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## Homework Statement

Eight 60-kg skaters join hands and skate down an ice rink at 4.6 m/s. Side by side, they form a line 12m long. The skater at one end stops abruptly, and the line proceeds to rotate rigidly about that skater. Find the angular speed.

## Homework Equations

[tex]L=I\omega[/tex]

[tex]I_{rod} = \frac{1}{3}ML^2[/tex]

## The Attempt at a Solution

I said that initial angular momentum = [tex]rmv = 6m \times 480kg \times 4.6m/s = 13248 kg m^2 /s[/tex]

final angular momentum = [tex]\frac{1}{3} \times 480 \times 12^2 \times \omega=23040\omega[/tex]

so

[tex]13248=23040\omega[/tex]

[tex]\omega=0.575 rad / sec[/tex]

which according to the book is wrong. In the book it said 0.537 rad /sec. What have I done wrong here?

thanks