1. The problem statement, all variables and given/known data A light, rigid rod l = 9.44 m in length rotates in the xy plane about a pivot through the rod’s center. Two particles of masses m1 = 9.1 kg and m2 = 2.5 kg are connected to its ends. Determine the angular momentum of the system about the origin at the instant the speed of each particle is v = 2.1 m/s. Answer in units of kgm2/s. 2. Relevant equations Lz=Iw I = mr2 I = (1/12)ML2 w = v/r 3. The attempt at a solution I used the above equations: Lz=Iw I = mr2 I = (1/12)ML2 w = v/r I = 1/12(9.1kg)((9.44)2)=67.578 I = 1/12(2.5kg)((9.44)2)=18.57 sum of I = 86.1431 Used w = v/r = ((2.1m/s))/(9.44/2)=0.444915 Lz=Iw (86.1431)(0.444915)=38.32639 I got it wrong, please help, what did I do wrong? Did I even approach the right way? Thanks.