1. The problem statement, all variables and given/known data A 4 g bullet traveling at 500 m/s strikes a disk of mass 1 kg and radius 10 cm that is free to rotate around an axis passing through its center. The bullet’s incoming path is 5 cm above the rotation axis and the bullet comes to rest in the position shown in the figure. At how many revolutions per second is the disk is rotating afterwards? (Ignore the mass of the bullet after it hits the disk.) https://gyazo.com/7ba8193726c76f57aa6c3ffa9e0c2930 the answer is 3.18 but i can't seem to figure out how to do this. 2. Relevant equations L(initial) = L (final) LDisk = 1/2MR^2 3. The attempt at a solution Here is what i got so far using conservation of angular momentum R* Mass of Bullet * Velocity of bullet * sin([PLAIN]http://physics-help.info/physicsguide/appendices/si_units_images/image002.gif[/I]) [Broken] = IDisk * ωFinal 0.1m * (0.004kg)(500)sin([PLAIN]http://physics-help.info/physicsguide/appendices/si_units_images/image002.gif) [Broken] = (1/2) (1kg) (0.1)^2 * ωFinal But i can't seem to figure what the theta is in this case and how to incorporate 5cm above the rotation axis into the problem.