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A 2kg object has a position vector r = -4t i + 3t^2 j (m). Find its angular momentum relative to the origin as a function of time.
The correct answer is -24t^2 k (kgm^2/s).
I know that L = r*p and p is mv
so I differentiate r to get v
v = -4 i + 6t j
do I just multiply 2 and the cross proudct of r and v? I don't know what to do because of the t in the equation for vector r.
The correct answer is -24t^2 k (kgm^2/s).
I know that L = r*p and p is mv
so I differentiate r to get v
v = -4 i + 6t j
do I just multiply 2 and the cross proudct of r and v? I don't know what to do because of the t in the equation for vector r.